A lift is moving with accleration a in upward direction then the force applered by mass m on the floor of lift will be
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the resultant force will be ma +mg
where g is the acceleration due to gravity
where g is the acceleration due to gravity
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here 'a' is the pseudo acceleration
and as the mass is in verical equillibrium so the
force due to mass and the normal reaction would be equal and opposite so the answer is
"m(a+g)"
and as the mass is in verical equillibrium so the
force due to mass and the normal reaction would be equal and opposite so the answer is
"m(a+g)"
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