A lift moves up and down with an acceleration of 2m/s^2.in each case, calculate the reaction of the floor on a man of mass 50kg standing in the lift
Answers
Answered by
14
Answer:
The reaction is 100N
Explanation:
Given data,
Acceleration(a)=2m/so
Mass(m)=50kg
Force(F)=required
From,
Force (F)=mass(m)×acceleration(a)
F=50kg × 2m/so
F=100N
HOPE IT'S HELPFULL
IF SO MARK ME AS BRAINLIEST PLYYYYYZZz
Answered by
3
Explanation:
I hope it helps.
Acceleration =2 m/s^2
Actual weight (w=MG) =50kg =500 N
Apparent weight(R) =?
Upward
F=R-mg
ma+mg=R
50*2 + 500=R
R=600N
Downward
Mg-R=F
Mg-ma=F
500-50*2=F
F=400N
Attachments:
Similar questions