Physics, asked by bukkadheeraj, 1 day ago


A lift moves upwards and downwards with an acceleration of 2 m/s". The ratio of apparent weights of a person in the lift is​

Answers

Answered by UniqueOne07
1

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(g−a) while moving downwards.

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(g−a) while moving downwards.Hence, as per the given information,

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(g−a) while moving downwards.Hence, as per the given information,m(g+a)=2m(g−a)

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(g−a) while moving downwards.Hence, as per the given information,m(g+a)=2m(g−a)g+a=2g−2a

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(g−a) while moving downwards.Hence, as per the given information,m(g+a)=2m(g−a)g+a=2g−2aHence, a=3g 

Answered by Anonymous
0

Answer:

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