a lift of mass 1000 kg is moving with an acceleration of 2m/s^2 in upward direction. calculate the tension developed in the string connected with lift.
Answers
Answer:
The mass of the lift is 1000kg, the acceleration is 1m/s
2
and the acceleration due to gravity is 9.8m/s
2
.
The tension developed in string is given as,
T=mg+ma
=1000×9.8+1000×1
=10800N
Thus, the tension developed in the string is 10800N.
Answer:
The tension developed in the string which is connected to the lift is 19,600 N.
Explanation:
Given: Mass, m = 1000 kg
g = 9.8 m/s²
To find: Tension in the string developed.
Solution: Let us draw the free body diagram of the above given case. (Refer to the attached image)
From the attached image, we conclude:
T - mg = ma ( as per Newtonian laws )
T = mg + ma
T = m (g +a)
T = 1000 ( 9.8 + 2 )
T = 1000 × 19.6
T = 19,600 N
Hence, the tension developed in the string which is connected to the lift is 19,600 N.
