Question

A lift performs the first part of its ascent with uniform acceleration

‘a’ and the remainder with uniform retardation 2a. Prove that is h is

the depth of the shaft and t is the time of ascent, then ℎ =1/3²​

Answer 1

Explanation:

We have t

1

=

a

v

and t

2

=

2a

v

Adding both times, we get

t=

2a

3v

...... (1)

or

h=h

1

+h

2

h=

2a

v

2

+

4a

v

2

h=

4a

3v

2

...... (2)

From (1) and (2), we get

h=

3

at

2

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