a lift starts from rest with some acceleration upward .A man throws a ball upward initially with speed u after t time then the ball comes in hand of man find acceleration of lift
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Answer:
2v/t
Explanation:
Take case with respect to the lift
Upward velocity with respect to lift v
As lift is moving upward with a acceleration
acceleration of ball with respect to the lift = acceleration of the ball – acceleration of lift
= – g – (a) = – (g+a)
using s=ut+(1/2)at2
as it again comes back to same position with respevt to lift therefore displacement is zero
0 = vt -(1/2)(a+g)t2
vt=(1/2)(a+g)t2
a+g = 2v/t
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