Physics, asked by rudradhandare, 8 months ago

a lift whose cage is 3 metre high is moving up with the acceleration of 2 metre per second square a piece of stone is dropped from the top of the cage of the lift when its velocity is 8 metre per second if gravitational is equal to 10 metre square then the store will reach the floor of the left after
answer \: with \: solution

Answers

Answered by navya7267
1

Answer:

0.3 s is the answer

Explanation:

The time taken to reach the stone on the floor is given as,

s=ut+

2

1

(a+g)t

2

3=8×t+

2

1

(2+10)t

2

3=8×t+6t

2

t=0.3052sec

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