Question

A light bulb has a resistance of 8 ohms and a maximum current of 10 A. How much voltage can be applied before the bulb will break?

Answer 1

Explanation:

R =8 ohm

I = 10A

V=?

by ohms law

V=R *I

= 8*10

=80VOLT

Answer 2

voltage = current x resistance.

= 10 x 8

= 80 volts.

hope this answer will be helpful to you dear.

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