a light bulb is rated at 100W for a 220V supply.Find the resistance of the bulb?
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Answered by
3
given that p=100w,v=220v
P=VI
100=220*I
I=100/220=5/11 Ampere.
we know that V=IR (ohms law)
220=5/11R
R=2420/5
R=484 ohm
P=VI
100=220*I
I=100/220=5/11 Ampere.
we know that V=IR (ohms law)
220=5/11R
R=2420/5
R=484 ohm
Answered by
1
(i) Power, P = VI
P = V x V/R
R = $V^{2}$ / P = 220 x 220 / 100 = 48400 / 100 = 484
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