Physics, asked by nooramohammed78, 4 days ago

A light bulb takes in 30J of energy per second. It transfers 3J as useful light energy and 27J as heat
energy. Calculate the efficiency.

can u answer this question?

Answers

Answered by Mfislam

1

Answer:

efficiency is 10%

Explanation:

eta= Pout/Pin × 100

= 3/30 ×100

= 10%

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