Question

A light bullet is fired from a heavy gun.A shell of mass 0.020 kg is fired by a gun of mass 100 kg .if the muzzle speed of the shell is 80m/s.what is therecoli speed of the gun?​

Answer 1

Answer:

0.16m/s

Explanation:

Mass of gun M = 100kg

mass of shell m = 0.020kg

Velocity of shell v = 80m/s

Recoil velocity of Gun V=?

initial velocities of both gun and shell will be zero

so, the initial momentum of the system will be zero.

According to the law of conservation of momentum,

Initial momentum = Final momentum

so,

0=mv-MV

∴v=mv/M

=

100

0.020×80

=0.016 m/s

∴recoil velocity of Gun=0.016m/s

Have a nice day dear

Answer 2

Given :-

Mass of the shell = 0.020

Mass of the gun = 100 kg

Speed of the shell = 80 m/s

To Find :-

The recoil of the gun.

Analysis :-

Here we are given with the mass of shell and gun and the velocity of the shell.

Using the law of conservation of momentum, you can easily find the recoil velocity of gun by substituting the values in the question.

Solution :-

We know that,

• m = Momentum
• mv = Final momentum
• MV = Initial momentum
• m = Mass

Using the formula,

$\underline{\boxed{\sf Initial \ momentum=Final \ momentum }}$

Given that,

Mass₁ = 0.020 kg

Mass₂ = 100 kg

Velocity₁ = 80 m/s

Substituting their values,

⇒ 0 = mv - MV

⇒ v = mv/M

⇒ v = 0.020 × 80 / 100

⇒ v = 1.6/100

⇒ v = 0.016 m/s

Therefore, the recoil speed of the gun is 0.016 m/s.