A light has amplitude A and angle between analyser and polariser is 60°. Light is reflected by analyser has amplitude(a) A √2(b) A / √2(c) √3 A / 2(d) A / 2
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answer : option (d) A/2
explanation : A light has amplitude A and angle between analyser and polariser is 60° .
light is reflected by analyser has amplitude = ?
we know, amplitude of light reflected by analyser , A' =
where, A is amplitude of light and is angle between analyser and polariser
so, A' = Acos60° = A/2
hence, option (D) A/2 is correct.
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Answer:
light is reflected by analyser having amplitude equals
A/2
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