Question

A light having wavelength 300 nm fall on a metal surface. The work function of metal is 2.54 eV, what is stopping potential?(a) 2.3 V(b) 2.59 V(c) 1.59 V(d) 1.29 V

Answer 1

answer should be option C approx.

Answer 2

Given that,

Wavelength, $\lambda=300\ nm$

The work function of metal, W = 2.54 eV

To find,

The stopping potential of metal.

Solution,

The Einstein's photoelectric equation is given by :

$\dfrac{hc}{\lambda}-W=eV_o$

$V_o$ is stopping potential

$(\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3\times 10^{-7}}\ J)-2.54\ e=eV_o\\\\6.63\times 10^{-19}\ J-2.54\ e=eV_o\\\\4.14\ eV-2.54\ eV=eV_o\\\\V_o=1.6\ eV$

So, the stopping potential is 1.6 eV.

Learn more,

Photoelectric equation

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