Question

a light incident at an interface at an angle 60 is refracted into another medium at an angle 30 if its speed in the first medium is c then its speed n the second medium is

Answer 1

according to Snell's law
c/n =1N2 = sini/sine
so, c/n = sin60°/sin30°

c/n= √3/2×2/1

c/n = √3

so, n = c/√3

c= 3 × 10to the power 8

thus speed n = √3 × 10^8 m/sec

I hope it helps

Answer 2

α= angle of incidence

β = angle of emergence

c = speed in medium 1

n = speed in medium 2

acc. to snell's law = c x sinα = n x sinβ

here α = 60, β = 30

so, c x sin60 = n x sin30

               c/n = sin30/sin 60

                     = 1/2 x 2/$\sqrt{3}$

                     = $\sqrt{3}$

                  ∴ n = c/$\sqrt{3}$

hope it helped

:)