Question

a light incident at an interface at an angle of 60 degree is refracted into another medium at angle 30 degree if its speed in first medium is C then its speed in second medium is ​

Answer 1

Answer:

μ2μ1=sinisinr=velocity in medium 1velocity in medium 2

30o=Cv⇒

v=C×sin30osin 60o=C3

Explanation:

Let us take two medium 1 & 2 with refractive indices μ1 and μ2 respectively.

Let the speed of light in medium 2 be v.

Using Snell's law, we have

Answer 2

Answer:

according to Snell's law

c/n =1N2 = sini/sine

so, c/n = sin60°/sin30°

c/n= √3/2×2/1

c/n = √3

so, n = c/√3

c= 3 × 10to the power 8

thus speed n = √3 × 10^8 m/sec

I hope it helps

Explanation: