Question

A light of wavelength 414 nm is used in an experiment on photoelectric effect with lithium (work function = 2.50V). The maximum kinetic energy of the photoelectrons
us
(h=4.14 x 10-15 eVs; c= 3 x 10 m/sec)​

Answer 1

Answer:

K.E=0.46eV

Explanation:

$k.e = \frac{hc}{wavelength} - work \: function$

Therefore hc = 1240eV/c

$= \frac{1240}{414} - 2.50 = 2.99 -2.50$

= 0.49eV

Answer 2

Answer:

Explanation:

Given - A light of wavelength 414 nm is used in an experiment on photoelectric effect with lithium .

To Find -  Find the maximum kinetic energy of the photo electrons .

A wavelength is the horizontal distance between the wave's two peaks. The wavelength of light is used to quantify it . It is commonly represented by the Greek sign. The wavelengths of visible light are often specified as 400–700 nanometers (nm), or one billionth of a metre.

K.E = 0.46 eV

$k.e = \frac{hc}{wavelength} - work function$

Therefore,

hc = $1240$eV/c

$\frac{1240}{414} - 2. 50 = 2. 99 - 2.50 \\= 0. 49 eV$

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