A light ray enters from air to a medium whose refractive index is 1.33 times the refractive index of air.The ratio of speed of light in respective media is ? [ Take speed of light in air as 3 · 10^{8}
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Answered by
1
refractive index of medium = 1.33
refractive index of medium = speed of.light in air/speed of light in medium
thus
1.33 = 3 * 10^8 / speed of.light in medium
speed of.light in medium = 2.25 * 10^8 m/s.
refractive index of medium = speed of.light in air/speed of light in medium
thus
1.33 = 3 * 10^8 / speed of.light in medium
speed of.light in medium = 2.25 * 10^8 m/s.
dhruvsh2:
no problem
Answered by
1
Let the speed of light in medium be x
Then n=C/V (c=speed of light in vaccum, v=speed of light in medium)
1.33=3.10^(8)/x
x=3.10^(8)/1.33
=300*10^(8)/133 (multiply num and denom by 100)
=2.25*10^(8)
Speed Of light in medium=2.25*10^(8)
Hope this Helped YOU Cheers
Then n=C/V (c=speed of light in vaccum, v=speed of light in medium)
1.33=3.10^(8)/x
x=3.10^(8)/1.33
=300*10^(8)/133 (multiply num and denom by 100)
=2.25*10^(8)
Speed Of light in medium=2.25*10^(8)
Hope this Helped YOU Cheers
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