Question

a light ray enters into a liquid at an angle of 45° and gets reflected at an angle of 30° with respect to normal calculate the refractive index of the liquid if sine 45 =0.7 and sin 30°equal to 0.5

Answer 1

n1 x sin theta1 = n2 x sin theta2
1 x sin 45 = n2 x sin30 (if the 1st media is air, whose refractive index is 1)
0.7 = n2 x 0.5
n2 = 7/5
n2 = 1.4

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Answer 2

Refractive index is the measurement of the bend in the light ray when it enters into one medium from another.

The equation used is, n = sin i/sin r where n is the refractive index, sin I is the angle of incidence and sin r is the angle of refraction.  

Given in the question, sin i = sin 45 = 0.7 and sin r = sin 30 = 0.5.

Therefore n = sini/sinr = sin 45/sin 30 = 0.7/0.5 = 1.4