A light ray falls on the surface of water (RF of water 4/3) at angle of incidence 45 degrees. What is the angle of refraction for this ray?
Answers
Answered by
3
we know by Snell's law : μ = refractive index = Sin i / Sin r
where i = angle of incidence in air/vacuum = 45⁰ =π/4
r = angle of refraction in water
μ = refractive index of water = 4/3
Sin r = Sin 45⁰ / (4/3 ) = 3/4√2 = 0.53
r = 32°
where i = angle of incidence in air/vacuum = 45⁰ =π/4
r = angle of refraction in water
μ = refractive index of water = 4/3
Sin r = Sin 45⁰ / (4/3 ) = 3/4√2 = 0.53
r = 32°
kvnmurty:
click on thanks button above please
Similar questions