Question

A light ray in a medium of refractive index n1 is partially reflected and refracted at the boundary of refractive index n2 if the angle BOC=90 the value of angle thetha 1 is given by ? HINT ( sin(pi/2-thetha)=cos thetha PLZ HELPPPPPP

Answer 1

Answer:

ANSWER

From Snell's Law, μ=

sinr

sini

As r=

2

i

So, μ=

sin

2

i

sini

=

sin

2

i

2sin

2

i

cos

2

i

=2cos

2

i

⇒cos

2

i

=

2

μ

⇒

2

i

=cos

−1

2

μ

⇒i=2cos

−1

2

μ

.

Answer 2

Answer:

sorry I don't know....................