Question

A light ray is incident at an angle 45 on parallel sided glass slab and emerges out grazing the vertical surface. The refractive index of the slab is

Answer 1

$\sqrt{\frac{3}{2} }$

Explanation:

Given that,

The Incident angle of light ray(i) = 45°

Now, by employing Snell's law

Refractive Index(μ) = sin i /sin r

because it at grazing angle,

r = 90 − c

∵ μ = sin i/cos c

As we know, critical angle i.e.

sin c = 1/μ

and Cos c = $\sqrt{1 - sin^2c}$

By putting the values,                         (i = 45°)

1/$\sqrt{2}$ = μ$\sqrt{1 - 1/u^2}$

1/2 = μ^2$\sqrt{1 - 1/u^2}$

μ^2 = 3/2

∵ μ = $\sqrt{\frac{3}{2} }$

Learn more: Refractive Index

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