A light ray is incident at an angle of 45 with the normal
mahakincsem:
compete question is "A light ray is incident at an angle of 45 with the normal to a 2 cm thick plate (μ= 2 ). Find the shift in the path of the light as it emerges out from the plate."
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The correct option is 0.42 cm
Explanation:
Lateral displacement is given by
x= tsin(i−r) /cosr
Now using Snell's law, we get
1×sini=μ×sinr
note : sin r= 1/√2+1/√2+1/√2
since, r=30°
Hence, x= (√2 x sin (45° -30° ))/cos30°
Thus,
x = √2 x ((√3-1)/2√2)/(√3/2)
This give, x = 0.42 cm
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