Question

A light ray of angle of incidence 40° emerged from the prism in minimum deviation position. Then what is the
angle of incidence on the second surface?
(1) 90°
(2) 0°
(3) 40°
(4) 20°​

Answer 1

Answer:

40° , cz at minimum deviation i=e

Answer 2

Angle incidence on the second surface is $40^o.$

Given :

Angle of incident of light ray at minimum deviation position , $d = 40^o$.

We need to find the angle of incidence.

We , know at minimum deviation . The light inside the prism is parallel to its base.

Therefore, incident angle will be same as the emergent angle.

So, angle incidence on the second surface is $40^o.$

Hence, this is the required solution.

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Refraction

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