A light ray originating from water strikes on water-air interface with an angle of incidence 49 degree .The angle of refraction on air medium is??
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Speed of the light in air = 3 × 10⁸ m/s.
Speed of the light in Water = 2.25 × 10⁸ m/s.
∴ Refractive Index of air with respect to water = 2.25 × 10⁸/3 × 10⁸
= 2.25 /3
= 0.75
Now, Using the Formula,
Refractive Index of air w.r.t water = Sin i/Sin r
⇒ 0.75 = Sin 49°/Sin r
⇒ Sin r = Sin 49/0.75
⇒ Sin r = 0.75°/0.75 [Sin 49° is 0.75]
∴ Sin r = 1
⇒ Sin r = Sin 90
On Comparison,
r = 90°
Hope it helps.
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