Question

a light ray travels along 3x +2y =5 strikes the line x+y=2 and gets reflected .find the equation of the reflected ray

Answer 1

Answer:

See Fig. We have

x - 2y + 5 = 0 (Incident ray ..(1)

x - 2y + 7 = 0 (Surface line) ....(2)

P = (−1, 2) is the point of incidence of the lines given in Eqs. (1) and (2). Hence, the equation of the normal at P(−1, 2) is

y - 2 = -2/3(x + 1)

2x + 3y - 4 = 0 ....(3)

Let m be the slope of the reflected ray. Since the normal at P makes equal angles with the incident line and reflected line, we have

However, m ≠ 1 2/ . So that the reflected line is

y - 2 = 29/2(x +1)