Question

A light rod of length 1 has two masses m, and m,
attached to its two ends. The moment of inertia of
the system about an axis perpendicular to the rod
and passing through the centre of mass is
[NEET (Phase-2) 2016] my
m.m2 1²
(1) ma+M2
(2)
m₂ + m2 2
mm2
(3) (m, + m₂)? (4) ✓m, mz1²
ufmodius R and mass M, a circular​

Answer 1

Answer:

Total moment of inertia = moment of inertia due to rod at the centers + due to two masses

Explanation:

l = MR^2/12 +2MR^2