Question

A light rod with two point charges q and - q both of mass m are attached at its end is placed in a region of uniform electric field with intensity E as shown in the figure. The angular acceleration of rod at the instant shown is

Answer 1

Answer:

The angular acceleration of the rod at the instant is ∝ = 2qEθ/ Ml

Explanation:

Torque = Force x perpendicular distance

Z = qE. l x sinθ

OR

Z = qElsinθ

Also ewe know that

Z = I∝

Here

∝ is angular acceleration.

So ∝ = Z / I

I = Ml^2 / 2

∝ = qElsinθ / Ml^2 / 2

∝ = 2qElsinθ / Ml

∝ = 2qEθ/ Ml

Thus The angular acceleration of the rod at the instant is ∝ = 2qEθ/ Ml

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