Chemistry, asked by sujitha639, 11 months ago

a light source of wavelength Lambda illuminate a metal and ajax photoelectron with ke Max is equals to one electron volt another light source of wavelength Lambda battery that photo electrons from a metal with km is equals to 4 electronic the value of work function is 0.1 X then the value of x is​

Answers

Answered by antiochus
4

Answer:

K_{max} =\frac{hc}{lamda}λ-Ф

K_{max} =it is the maximum kinetic energy of photoelectric with the wave length of the light producing the photo electron

K_{1} =\frac{hc}{λ1}

K_{2} =\frac{hc}{λ}

λ2=\frac{1}{3}λ1

K_{2} -3K_{1} =K_{1}

Φ=2eV K_{1} =1eV and K_{2} =5eV

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