a light string passes over a frictionless Pulley to one of its and a mass of 6 kg is attached and two its other in same mass of 10 kg is attached the tension in the thread will be
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75 Newton is the tension force
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Answered by
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Answer:75N
Explanation:T-6g=6a --(1)
10g-T=10a ---(2)
Adding 10g-6g=10a+6a
So a=4g/16 =g/4
T=10g-10a
=100-10×10/4
=75N
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