Question

A light string passing over a smooth light pulley connects two blocks of masses m1 and m2(vertically). If the acceleration of the system is g/8 then the ratio of the masses is

Answer 1

Answer:

m1:m2=?

Explanation:

T-m1g=m1a

m2g-T=m2a

T=m1g+m1a=m1(g+a)

T=m2a-m2g=m2(a-g)

we know that a=g/8

m1/m2=g+g/8÷g-g/8=9g/7g=9/7.

hence m1:m2= 9:7.

hope it's helps u