Question

A light vehicle of mass 50 kg starting from rest with an acceleration of 4m/s-2 travels for 50m. The time taken by the vehicle is

Answer 1

your ans is......
firstly, u=0,a=4,s=50.
by using Newton second law of motion...
s=ut+1/2at square
50=1/2×4×T square
then t=5
hence time taken by vehicle is 5s

Answer 2

The time taken by the vehicle is 5 seconds.

Explanation:

It is given that,

Mass of the vehicle, m = 50 kg

Initial speed of the vehicle, u = 0

Acceleration of the vehicle, $a=4\ m/s^2$

Distance, d = 50 m

Let t is the time taken by the vehicle. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$t=\sqrt{\dfrac{2d}{a}}$

$t=\sqrt{\dfrac{2\times 50\ m}{4\ m/s^2}}$

t = 5 seconds

So, the time taken by the vehicle is 5 seconds. Hence, this is the required solution.

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Second law of motion

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