Question

A light vehicle of mass 50 kg starting from rest with an acceleration of 4 ms travels for 50 m. The time taken by the vehicle is b) 5s c) 63 d) 73​

Answer 1

Solution :-

We know that,

$\boxed{\bf{s = ut +\frac{1}{2} at^2}}$

• Here, it started from rest so u = 0

a = 4m/s^2

s = 50m

u = 0

$\rightarrow\:\:\bf{50 = (0)t +\frac{1}{2} *4*t^2}$

$\rightarrow\:\:\bf{50 = \frac{2}{1}*t^2}$

$\rightarrow\:\:\bf{\frac{50}{2} = t^2}$

$\rightarrow\:\:\bf{t^2} = 25$

$\rightarrow\:\:\bf{t} = \sqrt[2]{25}$

$\rightarrow\:\:\bf{t} = 5\:s$

Final Answer :-

$\rightarrow\:\:\bf{time\:taken = 5\:s}$

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