Physics, asked by kadubalu13, 3 days ago

A light wave of frequency 4 × 1014 Hz and speed 3 × 108 m/s enters glass of R.I. 1.5. What is the change in its wavelength?

Answers

Answered by kritika9rajput

0

Answer:

λa=van=3×1084×1014=0.75×10−6

=7500Å

Explanation:

λg=λaμg=75001.5=5000Å

λa−λg=7500−5000=2500Å

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