Question

A light wire of length l and radius r is welded to
another light wire of length I and radius 2r. Taking
the modulus of elasticity of each wire as y, the ratio
of extension produced in first wire to 2nd wire is​

Answer 1

Answer:

Hope it helps you..........

Answer 2

Answer:

∆l1/∆l2=1/2

Explanation:

change in length

∆l =l/R2

∆l1/∆l2=L1/L2*R2^2/R1^2

∆l1/∆l2=2L/L*R/4R

∆l1/∆l2=1/2

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