Question

A lighter body and heavier body both are moving with same momentum and applied same retarding force. Their stoping distances are s₁ and s₂ respectively. Then the correct relation between s₁ and s₂ -​

Answer 1

Answer:

SOLUTION

G

i

v

e

n

m

1

v

1

=

m

2

v

2

.

L

e

t

m

1

>

m

2

⇒

v

2

<

v

1

a

1

=

F

m

1

a

n

d

a

2

=

F

m

2

,

where F is the applied force.

We have,

O

=

v

1

−

a

1

t

1

⇒

t

1

=

v

1

a

1

=

m

1

v

1

f

O

=

v

2

−

a

2

t

2

⇒

t

2

=

v

2

a

2

=

m

2

v

2

f

⇒

t

1

=

t

2

Also,

O

=

v

2

1

−

2

a

1

s

1

⇒

s

1

=

v

2

1

2

a

1

=

(

m

1

v

1

2

F

)

v

1

O

=

v

2

2

−

2

a

2

s

2

⇒

s

2

=

v

2

2

2

a

2

=

(

m

2

v

2

2

F

)

v

2

S

2

>

s

1

s

i

n

c

e

v

2

>

v

1

Answer 2

Answer:

solution

G

i

V

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