A line AB is drawn through the point of intersection of the diagonals of a parallelogram as shown in the figure: (i) In AROA: APOB? Given reasons. (ii) Is OA= OB? Justify your answer.
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Given that,
1)AB is a intersection on diagonals
∆AOR=∆POB are equal because opposite intersecting angles are congruent and equal in area so proved that
∆AOR=∆POB
2)OA=OB because it is equally divided into two by intersecting SQ,PR
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