A line AB meets the x-axis at point A and y-axis at the point B the point P (-4,-2)divides the line segment AB internally such that AP :PB=1:2 find the coordinates of A and B the equation of the line P and perpendicular to AB
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Let point A=(x,0) and B=(0,y) .By using the internal formula which is in the ratio 1:2 ,i got x=-6 and y=6 .Find the slope of (-6,0) and(0,6) and slope of perpendicular line will be -1/slope as we got above and from slope point form we will get equation which we required . x-y+2=0
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