A line AB of length 85mm is inclined 45 degrees to the horizontal plane and 60 degree with the vertical plane calculate the length of the projection in front view on vertical plane
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Answer:
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Explanation:
30
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Answer:
The front view of a line AB 80 mm long, measures 60 mm. The end A is 15 mm in front of VP and 10 mm above HP. The end B is in 3rd quadrant. Draw the projections of line, if the line is inclined 300 to HP. Also find inclination of line with VP.
Explanation:
Given Data:-
Distance between End Projectors (DBEP) = 40 mm
a’ (↑) = 15 mm
a (→) = 20 mm
θ = 30°
TL = ab2 = a’b1’ = 80 mm
Follow the procedure given below step by step to draw the projection of line –
Draw XY line.
Mark a’ and a at 15 mm above XY line and 20 mm below XY line respectively.
Draw horizontal line from a’ and a.
Draw TL (a’b1’) of 80 mm from point a’ at an angle of 30°.
Draw locus of b’ through point b1’.
Mark a point at DBEP = 40 mm measuring from point a’ and draw a vertical line from that point.
This vertical line will cut the locus of b’. Mark that point b’.
Join a’b’ (FV).
Taking a’ as center and a’b’ as radius draw an arc which will cut the horizontal line passing through a’, mark that point b2’.
Join a’b2’ (EL).
Take the projection of b1’ into TV (Draw a vertical line from point b1’) which will cut the horizontal line passing through point a. Mark that point b1, ab1 is your plan length (PL).
Taking a as centre and ab1 as radius draw an arc which will cut the locus of b, mark that point b. Join ab, that is your TV.
Draw a horizontal line from point b, that is your locus of b.
Take the projection of b2’ into TV (Draw a vertical line from point b2’) which will cut the locus of b. Mark that point b2.
Join ab2 (TL).
Measure the true inclinations Φ.
Answers –
enter image description hereΦ = 45°