Question

A line AB of length 85mm is inclined 45 degrees to the horizontal plane and 60 degree with the vertical plane calculate the length of the projection in front view on vertical plane

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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Given :-

Distance between End Projectors (DBEP)

= 40 mm

a (upward) = 15 mm

a (right) = 20 mm

= 30 degree

TL = ab2 = a'b1' = 80 mm

Follow the procedure given below step by step to draw the projection of line ---

Draw XY line.

Mark a' and a at 15 mm above xy line and 20mm below xy line respectively.

Draw horizontal line from a' and a .

Draw TL (a'b1') of 80 mm from point a' at an angle of 30°

Draw the locus of b' through point b1'.

Mark a point at DBEP = 40 mm measuring from point a and draw a vertical line from that point .

This vertical line will cut the locus of b'.

Mark that point b'.

Join a'b' (FV) .

Taking a' as centre and ab' as radius. Draw an arc which will cut the horizontal line passing through a' mark that point b2'.

Join a'b2' (EL) .

Take the prediction of b1' into TV (draw vertical line from point b1') which will cut the horizontal line passing through point a marked at point b1 a b is your plan length (PL) .

Taking a as centre and ab1 as radius draw an Arc which will cut the locus of b, mark that point b. join ab, that is your TV .

Draw a horizontal line from point b' that is your locus of b.

Take the projection of b2' into TV (draw vertical line from point b2) which will cut the locus of be marked at point b2.

Join ab2 (TL) .

Measure the true inclination.

enter image description here = 45 degree