A line cuts two sides AB and AC of ABC at the points P and Q respectively, then show that ABC ~APQ
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A line cuts two sides of triangle ABC through AB and AC know.
Then angle A= angle A [in both tri ABC and tri APQ]
PQ ll BC and AB is a transversal.
so angle B= angle P
similarly, angle C= angle Q.
by AAA similarity,
ABC similar to APQ
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