a line from the point (2, 3) is perpendicular to the line y = 1x/3 +1. the 2 lines meet at the point P. Find the coordinates of P
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given line is y=x/3 +1 -----A
slope of given line = 1/3
slope of perpendicular line = -3
equation of line perpendicular is
y = -3x+c
line passes through (2,3) so
3 = -6+c
c = 9
so equation is y = -3x+9 ---B
p is intersection of Aand B
solving A and B
x/3+1 = -3x+9
x+3 = -9x+81
10x = 78
x = 7.8
substitute in A
y = 3.6
so p is (7.8, 3.6)
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