Question

A line has a slope of -1/4 and passes through point (-5/4).What is the equation of the line

Answer 1

It is given that ,

Slope = -1/4

Point = (-5 , 4)

We know that , the point slope form is given by

$\large \sf \underline{ \: \fbox{ (y - y_{1}) = m(x- x_{1})} \: }$

Substitute the values , we obtain

$\sf \implies (y - 4) = - \frac{1}{4} (x - ( - 5)) \\ \\\sf \implies 4(y - 4) = - \frac{1}{4} (x + 4) \\ \\\sf \implies 4y - 16 = - x - 4 \\ \\\sf \implies x + 4y - 12 = 0$

Thus , the equation of the line is x + 4y - 12 = 0