Math, asked by XZomboX, 8 months ago

A line has a slope of Negative two-thirds and passes through the point (–3, 8). What is the equation of the line?
y = negative two-thirds x + 6
y = negative two-thirds x + 8
y = 6 x minus two-thirds
y = 8 x minus two-thirds

Answers

Answered by ake05814
1

Answer:

y = negative two-thirds x + 6

Step-by-step explanation:

the form of a equation of a line in y intercept for is in y=mx+b

m is the slope, so you put -2/3 there

next, we have to find b, which is the y interecept (when the line meets the y axis)

we can do this by substituting the point (-3,8) into the equation

(8)=-2/3(-3)+b

8=2+b

6=b

so the full equation of the line is y=-2/3x+6

Answered by tyrbylent
0

Answer:

y = - \frac{2}{3} x + 6

Step-by-step explanation:

m = - \frac{2}{3} and P(- 3, 8)

y - 8 = - \frac{2}{3} (x + 3)

y = - \frac{2}{3} x + 6

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