A line intersccts the y-axis and x-axis at the points P' ad Q respectively. If (2.-3) is the midpoint of PO, then the coordinatcs of P and Q will be=
(a) (0.-10) and (4,0)
(b) 4,0) and (10,0)
(c) (12,0) and (-4,0)
(d) (0.12) and (4,0)
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Let the co-ordiantes of P be (x,y) and Q be (x
2
,y
2
)
midpoint of PQ=(2,−5)
By midpoint formula,
x=
2
x
1
+x
2
and y=
2
y
1
+y
2
2=
2
x
1
+x
2
and −5=
2
y
1
+y
2
∴x
1
+x
2
=4 and y
1
+y
2
=−10
Since line PQ intersects the y-axis at P
So, x
1
=0.
Similarly, y
2
=0
∴x
2
=4 and y
1
=−10
The co-ordinates of P are (0,−10) and Q are (4,0).
Solve
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