Question

. A line intersects the y- axis and x-axis at the
point p and q respectively. if (2-5) is the
mid point of Pd, then the coordinates of Pand q
are, respectively​

Answer 1

Answer:

P = (0,-10) , Q = (4,0)

Step-by-step explanation:

Let the coordinates of point P be (0,x) since it lies on y-axis

also let the coordinates of point Q be (y,0) since it lies on x-axis

also coordinates mid-point M of PQ are given as (2,-5)

the ratio in which we need to cut the line m:n = 1:1

therefore,

after calculation we conclude that

$M = (\frac{mx_{2} + nx_{1}}{m+n},\frac{my_{2} + ny_{1}}{m+n})\\here, M = (2,-5)\\ (x_{1},y_{1}) = P = (0,x)\\ (x_{2},y_{2}) = P = (y,0)\\therefore,\\M = (\frac{1*y + 1*0}{1+1},\frac{1*0 + 1*x}{1+1})\\(2,-5) = (\frac{y}{2},\frac{x}{2})\\therefore,\\ 2 = \frac{y}{2}\ and -5 = \frac{x}{2}\\y = 4 \ and\ x = -10$

P = (0,-10) , Q = (4,0)