A line is drawn through the vertex parallel Parallel to the base of the triangle ABC, write the length
of PQ(distance between parallel lines) IN this way,how many triangles of same area can be drawn?
Answers
Answered by
2
Answer:
Correct option is
D
144
DE is parallel to AC
FG is parallel to BC
IH is parallel to AB
△PIE=49
△PDF=4
△PGH=9
△PGH≅△PIE
HP:PI=
9
:
49
=3:7
so, IP:IH=7:10
△PIE:△HIC=7
2
:10
2
area of △HIC=100
area of parallelogram PGCE=100−9−49=42
similarly,
are of parallelogram PIBF=(
4
+
49
)
2
−4−49
=81−53=28
are of parallelogram PDAH=(
4
+
9
)
2
−4−9
=25−13=12
are of △ABC=49+4+9+28+42+12=144
option D will be the correct answer
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