Question

A line is of length 10 and one end is at point(-3,2).If the ordinate of the other end be 10,prove that the abscissa will be 3 or -9.​

Answer 1

Answer:

Let point p be (-3, 2)

Let point q be (x, 10)

√(-3 - x) ^2 + √(2-10) ^2 = 10 units

Remove root and square the other side

(-3-x) ^2 +( -8) ^2 = 100

(-3-x) ^2 = 100 - 64

(-3-x) ^2 = ± 36

Now take the root of both the sides

-3-x= 6 | -3-x = -6

-x = 9 | -x = -3

x=-9 | x = 3

Hence Proved