Question

A line is of length 10 units and one end is at (2,-3).if the absissia of the other end is 10 , then its ordinate is

Answer 1

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we know that...
(distance.)^2
=(x2-x1)^2 + (y2-y1)^2
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now.......
according to the question..
here .......given that.........
d =10
x1 =2 x2=10
y1= -3 y2 = ?
now......
(10)^2 = (10 -2)^2 + (y2 +3)^2
100= 64 + (y2 +3)^2
(y2 +3)^2=36
(y2 +3) =6
(y2) = 6-3 =3
hence ... answer is (10, 3)
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it is answer
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