Question

A line is of length 10 units and one of its ends is (-2,3) . If the ordinate of the other end is 9, prove that the abscissa of the other end is 6 or -10 (coordinate geometry)

Answer 1

let the second Pt be (h, 9)
dist=((-2-h)^2 +(3-9)^2))^(1/2)=10
square both sides
4+h sq. +4h+36=100
h^2+4h-60=0
solve h=6,-10