a line is of the length 5 and one end is at the point (1, -2)if the abscissa of the other end is 4 prove that its ordinate must be 2or -6
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Hence Proved
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Step-by-step explanation:
5=√(4-1)^2+(y+2)^2
5^2=9+y^2+4+4y
25-13=y^2+4y
12=y^2+4y
y^2+4y-12=0
y^2+6y-2y-12=0
y(y+6)-2(y+6)=0
(y-2)(y+6)=0
y=-6,2
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